5x^2-2x-8=1

Solution for 5x^2-2x-8=1 equation:

5x^2-2x-8=1

We move all terms to the left:

5x^2-2x-8-(1)=0

We add all the numbers together, and all the variables

5x^2-2x-9=0

a = 5; b = -2; c = -9;
Δ = b2-4ac
Δ = -22-4·5·(-9)
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{46}}{2*5}=\frac{2-2\sqrt{46}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{46}}{2*5}=\frac{2+2\sqrt{46}}{10}
$